solve the equation:-
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Answer:
Given,
1/7x+1/6y= 3
Or, 6y+7x/42xy=3
Or, 6y+7x=126xy
Dividing both sides by xy, we get
6/x+ 7/y= 126
1/2x-1/3y= 5
Or, 3y-2x/6xy= 5
Or, 3y-2x= 30xy
Dividing both sides by xy, we get
3/x-2/y= 30
Let 1/x= a and 1/y= b.
Hence ,the two equations are. 3a-2b= 30....(1)
6a+7b= 126......(2)
Multiplying (1) by 2, and (2) by 1, we get:
6a-4b= 60.....(3)
6a+7b= 126......(4)
Substracting (3) from (4), we get
11 b= 66
Or, b= 6
Substituting b by 1/y we get
1/y= 6 or, y= 1/6.
Putting the value of a in(1) ,we get:
3a=30+2*6
Or, a= 42/3
Or,a = 14
Substituting a by 1/X, we get:
1/x= 14
Or, x= 1/14
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