Question

solve the equation 21x^2-4x+10=0​

Answer 1

Answer:

2 1 2 − 4 + 1 0 = 0

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

1

2

−

4

+

1

0

=

0

21x^{2}-4x+10=0

21x2−4x+10=0

=

2

1

a={\color{#c92786}{21}}

a=21

=

−

4

b={\color{#e8710a}{-4}}

b=−4

=

1

0

c={\color{#129eaf}{10}}

c=10

=

− ( − 4 ) ± ( − 4 ) 2 − 4 ⋅ 2 1 ⋅ 1 0 √2 ⋅ 2 1