Math, asked by deya77, 1 month ago

Solve the equation (2a^3*b^-2)^3

Answers

Answered by Anonymous
2

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 = (2 {a}^{3}  \times b ^{ - 2} )^{3}

 = (2 {a}^{3}  \times  \frac{1}{ {b}^{2} } )^{3}

 = ( \frac{2 {a}^{3} }{ {b}^{2} } )^{3}

  = \frac{8 {a}^{9} }{ {b}^{6} }

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