solve the equation 2k²+3k+42=0
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Use the quadratic formula
=
−
±
2
−
4
√
2
k
=
−
b
±
b
2
−
4
a
c
2
a
k=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
2
+
3
+
4
2
=
0
2
k
2
+
3
k
+
42
=
0
2k2+3k+42=0
=
2
a
=
2
a=2
=
3
b
=
3
b=3
=
4
2
c
=
42
c=42
=
−
3
±
3
2
−
4
⋅
2
⋅
4
2
√
2
⋅
2
k
=
−
3
±
3
2
−
4
⋅
2
⋅
42
2
⋅
2
k=2⋅2−3±32−4⋅2⋅42
=
−
±
2
−
4
√
2
k
=
−
b
±
b
2
−
4
a
c
2
a
k=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
2
+
3
+
4
2
=
0
2
k
2
+
3
k
+
42
=
0
2k2+3k+42=0
=
2
a
=
2
a=2
=
3
b
=
3
b=3
=
4
2
c
=
42
c=42
=
−
3
±
3
2
−
4
⋅
2
⋅
4
2
√
2
⋅
2
k
=
−
3
±
3
2
−
4
⋅
2
⋅
42
2
⋅
2
k=2⋅2−3±32−4⋅2⋅42
Answered by
1
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