Question

Solve the equation

( 2x + 1 ) (3x + 2 ) = 6 ( x- 1) ( x - 2).​

Answer 1

Step-by-step explanation:

(2x + 1)(3x + 2) = 6(x - 1)(x - 2)

6x² + 4x + 3x + 2 = (6x - 6)(x - 2)

6x² + 7x + 2 = 6x² - 12x - 6x + 12

6x² + 7x + 2 = 6x² - 18x + 12

6x² - 6x² + 7x + 18x - 12 + 2 = 0

25x - 10 = 0

i hope its helpfull

Answer 2

$\huge \boxed{ \bold{Answer}}$

=>(2x+1)(3x+2)=6(x–1)(x–2)

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]=>6x²+7x+2=6[x²–3x+2]

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]=>6x²+7x+2=6[x²–3x+2]=>6x²+7x+2–6x²+18x–12=0

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]=>6x²+7x+2=6[x²–3x+2]=>6x²+7x+2–6x²+18x–12=0=>7x+18x=10

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]=>6x²+7x+2=6[x²–3x+2]=>6x²+7x+2–6x²+18x–12=0=>7x+18x=10=>25x=10

=>(2x+1)(3x+2)=6(x–1)(x–2)=>2x(3x+2)+1(3x+2)=6[x(x–2)-1(x–2)]=>6x²+7x+2=6[x²–3x+2]=>6x²+7x+2–6x²+18x–12=0=>7x+18x=10=>25x=10=>x=10/25

=>x=2/5