Math, asked by sarahb2005, 9 months ago

solve the equation 2x^2+8x-1=0 by completing the square

Answers

Answered by ashutosh3184
2

Answer:

2

x

2

+

8

x

+

1

=

0

Subtract

1

from both sides of the equation.

2

x

2

+

8

x

=

1

Divide each term by

2

and simplify.

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x

2

+

4

x

=

1

2

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of

b

.

(

b

2

)

2

=

(

2

)

2

Add the term to each side of the equation.

x

2

+

4

x

+

(

2

)

2

=

1

2

+

(

2

)

2

Simplify the equation.

x

2

+

4

x

+

4

=

7

2

Factor the perfect trinomial square into

(

x

+

2

)

2

.

(

x

+

2

)

2

=

7

2

Solve the equation for

x

.

x

=

±

14

2

2

The result can be shown in multiple forms.

Exact Form:

x

=

±

14

2

2

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