Question

solve the equation 2x÷3 + 1 = 7x ÷15 +3 a) 10 b) 15 c) 14 d) 9​

Answer 1

Step-by-step explanation:

Correct option is

A

0

Given,

3

2x

+1=

15

7x

+3

MultiplyingbothsidesbytheLCMof3and15i.e.,15,weget

15(

3

2x

+1)=15(

15

7x

+3)

10x+15=7x+45

⇒10x−7x=45−15[Transposing7xtoLHSand15toRHS]

⇒3x=30

⇒x=10

Check:

LHS =

3

2x

+1=

3

2×10

+1=

3

20

+1=

3

20+3

=

3

23

RHS=

15

7x

+3=

15

7×10

+3=

3

14

+3=

3

14+9

=

3

23

Clearly, LHS = RHS

Hence checked!!

Answer 2

Answer:

${\large{\underline{\sf{Solution-}}}}$

Question,

${\longrightarrow{\sf{ \frac{2x}{3} + 1 = \frac{7x}{15} + 3 }}}$

By Doing LCM,

${ \longrightarrow{ \sf{ \frac{2x + 3}{3} = \frac{7x + 45}{15} }}}$

Now,

${ \longrightarrow{ \sf{3(7x + 45) = 15(2x + 3)}}}$

${ \longrightarrow{ \sf{21x + 135 = 30x + 45}}}$

${ \longrightarrow{ \sf{135 - 45 = 30x - 21x}}}$

${ \longrightarrow{ \sf{90 = 9x}}}$

${ \longrightarrow{ \sf{x = \frac{90}{9} }}}$

${ \longrightarrow{ \sf { \pmb{x = 10}}}}$

${ \therefore{ \underline{ \rm{ \pmb{ \pink{ Option \: A \: is \: your \: Answer }}}}}}$

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