solve the equation (2x-3)(6x-1)(3x-2)(x-12)-7=0
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Answer:
36x^4 - 456x³ + 997x² - 594x + 72
Step-by-step explanation:
take 2 sets at a time
(2x-3)(6x-1) = 12x² - 20x + 3
(3x-2)(x-12) = 3x² - 38x + 24
now multiply the two simplified workings
(12x² - 20x + 3)(3x² -38x + 24)
= 36x^4 - 456x³ + 288x² - 60x² + 760x² - 480x + 9x² - 114x + 72
= 36x^4 - 456x³ + 997x² - 594x + 72
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