Question

Solve the equation 2x^3-x^2-18x+9=0,if the two of the roots are equal in magnitude but opposite in sign.​

Answer 1

Answer:

Step-by-step explanation:

2x³-x²-18x+9=0

x³+x³-x²-18x+9=0

x³+x²(x-1)-9(x-1)=0

x³+(x²-9)(x-1)=0

Answer 2

Answer:

23−12−18+9=02x^{3}-1x^{2}-18x+9=02x3−1x2−18x+0

# hope it helps