Question

solve the equation 2x+y-5= 0 and 3x-2y-4=0 by eliminations method

pls find the answer frnds​

Answer 1

Answer:

Question

✳️solve the equation 2x+y-5= 0 and 3x-2y-4=0 by eliminations method

Solution ⬇️

✳️2x+y-5=0;3x-2y-4=0... putting in proper sequence

✳️2x+y=5;3x-2y=4

✍️2x+y=5...(1)x2

✍️3x-2y=4...(2)

✍️4x+2y=10...(3) multiplied eq 1 from 2

✍️7x=14 ...(by adding eq 3 and 2)(-2 and +2 will be cancelled)

$= = > x = \frac{14}{7}$

✍️x=2

➡️ putting x=2 in equation 1

✍️2x+y=5..(1)

✍️2(2)+y=5

✍️4+y=5

✍️y=5-4

✍️y=1

➡️(x,y)(2,1) is the solution of the given quadratic equation

__________________________

Important thing to remember

• If the greater sign is {(-)} then the answer will come in {(-)} sign only
• if the greater sign is {(+)} then the answer will come in {(+)} sign only

Step-by-step explanation:

hope you appreciate this ans

Answer 2

Question

✳️solve the equation 2x+y-5= 0 and 3x-2y-4=0 by eliminations method

Solution ⬇️

✳️2x+y-5=0;3x-2y-4=0... putting in proper sequence

✳️2x+y=5;3x-2y=4

✍️2x+y=5...(1)x2

✍️3x-2y=4...(2)

✍️4x+2y=10...(3) multiplied eq 1 from 2

✍️7x=14 ...(by adding eq 3 and 2)(-2 and +2 will be cancelled)

==>x=147= = > x = \frac{14}{7}==>x=

7

14

✍️x=2

➡️ putting x=2 in equation 1

✍️2x+y=5..(1)

✍️2(2)+y=5

✍️4+y=5

✍️y=5-4

✍️y=1

➡️(x,y)(2,1) is the solution of the given quadratic equation

__________________________

Important thing to remember

If the greater sign is {(-)} then the answer will come in {(-)} sign only

if the greater sign is {(+)} then the answer will come in {(+)} sign only

Step-by-step explanation:

hope you appreciate this ans