Question

solve the equation 2x+y =5 2x-5y+1=0 by substitute method​

Answer 1

$\bf\underline{\underline{\red{SOLUTION:-}}}$

Question

• Solve the equation 2x+y =5, 2x-5y+1=0 by substitute method?

Answer

• Value of x = 2
• Value of y=1

Given

• 2x+y=5
• 2x-5y+1 =0

To Calculate

• Value of x and y

Explanation

• 2x+y=5

➺ 2x =5-y

➺ x= (5-y)/2

Putting value of x in eq 2

• 2x-5y+1 =0

➺ 2×(5-y/2)-5y+1=0

➺ (10-2y)/2 -5y/1 +1/2 =0

Take LCM

➺ (10-2y-10y+2)/2 =0

➺ 10-2y-10y+2=0

➺ 10-12y+2=0

➺ 12-12y=0

➺ -12y=-12

➺ y= -12/-12

➺ y= 1

putting value of y in eq 2

• 2x-5y+1 =0

➺ 2×x-5×1+1=0

➺ 2x -5+1=0

➺ 2x-4=0

➺ 2x=4

➺ x= 4/2

➺ x= 2

$\bf\underline{\underline{\red{HENCE:-}}}$

• Value of x = 2
• Value of y=1

_________________________________________

Answer 2

Answer:

2x+y=5

- 2x =5-y

> X= (5-y)/2

Putting value of x in eq 2

• 2x-5y+1 =0

> 2x(5-y/2)-5y+1=0

(10-2y)/2 -5y/1 +1/2 =0

Take LCM

> (10-2y-10y+2)/2 =0

> 10-2y-10y+2=0

→ 10-12y+2=0

> 12-12y=0

> -12y=-12

> y= -12/-12y= 1

putting value of y in eq 2

• 2x-5y+1 =0

-> 2xx-5x1+1=0

- 2x -5+1=0

» 2x-4=0

2x=4

- X= 4/2

X= 2

HENCE:

• Value of x = 2

Value of y=1