solve the equation 2x²-5x+3=0 by completing square method
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Solution:
2x²-5x+3 = 0
=> 2x²-5x = -3
Divide each term by 2 , we get
=> x²-(5x/2) = -3/2
=> x² -2*x*(5/4) = -3/2
=> x²-2*x*(5/4)+(5/4)²=-3/2+(5/4)²
=> (x-5/4)² = -3/2+25/16
=> (x-5/4)²=(-24+25)/16
=> (x-5/4)² = 1/16
=> x-5/4 = ±√(1/16)
=> x = 5/4± 1/4
=> x = (5±1)/4
=> x = (5+1)/4 or x = (5-1)/2
=> x = 3/2 or x = 2
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