Question

solve the equation 2y+1=21 by the trial and error method
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Answer 1

Answer:

putting p = -3 in equation

5(-3) +2 = 17

-15+2 = 17

-13\ne17−13

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=17

putting p = -2 in equation

5\left(-2\right)+2=175(−2)+2=17

-10+2=17−10+2=17

-8\ne17−8

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=17

putting p =-1

5\times\left(-1\right)+2\ =\ 17\5×(−1)+2 = 17

-5+2=17−5+2=17

-3\ne17−3

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=17

putting 0 in the equation

5\times0\ +2\ =\ 17\5×0 +2 = 17

2\ne172

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=17

putting p =1 n the equation

5\times1+2=175×1+2=17

5+2=175+2=17

7\ne177

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=17

puttin p = 2 in the equation

5\times2\ +2\ =\ 17\5×2 +2 = 17

10+2\ =\ 17\10+2 = 17

12\ne1712

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=17

putting p = 3 in the equation

5\times3+2=175×3+2=17

15+2=1715+2=17

17=17\17=17

As LHS=RHS

p=3 is the solution

Step-by-step explanation:

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Answer 2

Answer:

2y+1=21

2y=21-1

2y=20

y=

$\frac{20}{2}$

=10