Question

solve the equation 2y+3/2y-5=y+1/y-1​

Answer 1

Step-by-step explanation:

I'm not sure that its the right answer

so once verify it

hope it may be helpful

Answer 2

Answer:

y = -2

Step-by-step explanation:

2y+3/2y-5 = y+1/y-1 [ "x" means the multiplication sign ]

=> (2y+3) x (y-1) = (y+1) x (2y-5) [Addition of brackets in this step]

=> [(y x 2y) + (y x 3)] - [(1 x 2y) + (1 x 3)] = [(y x 2y) - (y x 5)] + [(1 x 2y) - (1 x 5)] (Multiplying)

=> [2$y^{2}$ + 3y] - [2y + 3] = [2$y^{2}$ - 5y] + [2y - 5] (Multiplying completed]

=> 2$y^{2}$ + 3y -2y + 3 = 2$y^{2}$ - 5y + 2y -5 (Removing the brackets)

=> 2$y^{2}$ + y + 3 = 2$y^{2}$ - 3y - 5 (Adding & Subtracting)

=> 2$y^{2}$ - 2$y^{2}$ = - 3y - y - 5 - 3

=> 0 = - 4y - 8

=> 4y = -8

Therefore, y = -8/4

y = -2

after this step I don't know, but all I know is y = -2

I don't think this helped you, if it did, can you help ME by marking this answer as brainliest? [This took me like 20 minutes to solve this, pls consider me brainliest lol]