Math, asked by jashansidhu0647, 9 months ago

solve. the equation 2y-3/4+3y-1/2=y+1/4​

Answers

Answered by MemonMahin07
0

Step-by-step explanation:

2y -  \frac{3}{4}  + 3y -  \frac{1}{2}  = y +  \frac{1}{4}  \\  \\ 2y + 3y -  \frac{3}{4}  -  \frac{1}{2}  =  \frac{4y + 1}{4}  \\  \\ 5y -  \frac{6 - 4}{8}  =  \frac{4y + 1}{4}  \\  \\ 5y -  \frac{10}{8}  =  \frac{4y + 1}{4}  \\  \\ 5y -  \frac{5}{4}  =  \frac{4y + 1}{4}  \\  \\  \frac{20y - 5}{4}  =  \frac{4y + 1}{4}  \\  \\ 80y - 20 = 16y + 1 \\ 80y - 16y = 20 + 1 \\  64y = 21 \\  \\ y =  \frac{21}{64}

Answered by tanyabiru
0
Tsestesrrtsstrerfddfxhg
Similar questions