Question

Solve the equation 3^(2x+1)-28(3^(x-1) )+1=0

Answer 1

Answer:

3^2x+1-28(3^x-1)+1=0

We add all the numbers together, and all the variables

3^2x-28(3^x-1)+2=0

We multiply parentheses

3^2x-84x+28+2=0

We add all the numbers together, and all the variables

-84x+3^2x+30=0

We move all terms containing x to the left, all other terms to the right

-84x+3^2x=-30