Question

solve the equation 3(5a-2) + 5(2a+4) =4​

Answer 1

Step-by-step explanation:

15a -6+10a+20=4

25a+14=4

25a=-10

a=-10/25

a=-2/3

Answer 2

$\large\sf\underline{Question\::}$

Solve the equation :

• $\sf\:3(5a-2) +5(2a+4) =4$

‎

$\large\sf\underline{Answer\::}$

• The required value of a is $\large{\mathfrak\pink{\frac{-2}{5}}}$ .

_______________________‎

$\large\sf\underline{Given\::}$

Equation :

• $\sf\:3(5a-2) +5(2a+4) =4$

‎

$\large\sf\underline{To\:find\::}$

• Value of a

‎

$\large\sf\underline{Solution\::}$

$\sf\:3(5a-2) +5(2a+4) =4$

• Multiplying the terms

$\sf\dashrightarrow\:15a-6+10a+20 =4$

• Arranging and proceeding with required calculations

$\sf\dashrightarrow\:15a+10a-6+20 =4$

$\sf\dashrightarrow\:25a+14=4$

• Transposing +14 to other side it becomes -14

$\sf\dashrightarrow\:25a=4-14$

$\sf\dashrightarrow\:25a=-10$

• Transposing 25 to other side it goes to the denominator

$\sf\dashrightarrow\:a=\frac{-10}{25}$

• Reducing it to lower terms

$\sf\dashrightarrow\:a=\cancel{\frac{-10}{25}}$

$\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:a\:=\:\frac{-2}{5}}}}}$ ★

‎

$\large\sf\underline{Verifying\::}$

For verifying we need to substitute the value of a which we got after calculation. Doing so if we get LHS = RHS then our answers would be correct.

‎

$\sf\:3(5a-2) +5(2a+4) =4$

$\sf\dashrightarrow\:15a-6+10a+20 =4$

• Let's substitute the value of a as $\sf\:\frac{-2}{5}$

$\sf\dashrightarrow\:15(\frac{-2}{5})-6+10(\frac{-2}{5})+20 =4$

• Multiplying the terms

$\sf\dashrightarrow\:(\frac{-30}{5})-6+(\frac{-20}{5})+20 =4$

• LCM of 5 and 1 = 5

$\sf\dashrightarrow\:\frac{-30-30-20+100}{5} =4$

$\sf\dashrightarrow\:\frac{-60-20+100}{5} =4$

$\sf\dashrightarrow\:\frac{-80+100}{5} =4$

$\sf\dashrightarrow\:\frac{20}{5} =4$

• Reducing it to lower terms

$\sf\dashrightarrow\:\cancel{\frac{20}{5}}=4$

$\sf\dashrightarrow\:4=4$

$\bf\:\leadsto\:LHS=RHS$

‎

$\large{\mathfrak\blue{hence\:verified\:!!}}$

_______________________‎

‎

!! Hope it helps !!