Question

Solve the equation √3. cosc+sinc=√2.​

Answer 1

Answer:

2nπ+

6

π

±

4

π

3

cosx+sinx=

2

Dividing both sides with

3+1

=2

2

3

cosx+

2

1

sinx=

2

1

⇒cos(x−

6

π

)=

2

1

=cos

4

π

⇒x−

6

π

=2nπ±

4

π

⇒x=2nπ+

6

π

±

4

π

Answer 2

If sin(40+θ)=b,0<θ<45,, find i)cos(70+θ)ii)cos(160+θ)