Question

Solve the equation 3 upon x plus 1 minus 1 upon 2 equal to 2 upon 3x minus 1 where x not equal to minus 1 and 1 upon 3

Answer 1

hope this answer will help you.

Answer 2

Answer:

The value of x are 1 and 3.

Step-by-step explanation:

we need to solve the expression for the value of x

$\frac{3}{x+1}-\frac{1}{2}=\frac{2}{3x-1}$

Take L.C.M in above expression

$\frac{6-(x+1)}{2(x+1)}=\frac{2}{3x-1}$

$\frac{6-x-1}{2(x+1)}=\frac{2}{3x-1}$

$\frac{5-x}{2x+2}=\frac{2}{3x-1}$

Multiply both the sides by $(2x+2)(3x-1)$

$(5-x)(3x-1)=2(2x+2)$

$15x-5-3x^{2}+x=4x+4$

subtract both the sides by 4x+4 in above expression,

$15x-5-3x^{2}+x-4x-4=0$

Combine like terms together,

$-3x^{2}+x+15x-4x-4-5=0$

$-3x^{2}+12x-9=0$

divide both the sides by -3  in above expression

$x^{2}-4x+3=0$

$x^{2}-x-3x+3=0$

$x(x-1)-3(x-1)=0$

$(x-1)(x-3)=0$

if x-1 =0  ⇒ x=1

if x-3 =0  ⇒  x=3

Hence, the value of x are 1 and 3.