Question

Solve the equation:3(y-5)+5y=(2y-3) ^2-(y+1) ^2+1

Answer 1

$3(y - 5) + 5y = {(2y - 3)}^{2} - {(y + 1)}^{2} + 1 \\ 3y - 15 + 5y = 4 {y}^{2} + 9 - {y}^{2} + 1 + 1 \\ 8y - 15 = 3 {y}^{2} + 11$

Answer 2

(y-5)=(2y) answers (14-)