Question

solve the equation √3²-√2x+3√3=0​

Answer 1

Answer:

x=(√2+√17i)/2√3  and (√2-√17i)/2√3

Step-by-step explanation:

√3x²-√2x+3√3=0

here, a=√3 ; b= -√2 ; c=3√3

D=b²-4ac

D=(-√2)²-4×√3×3√3

D=2-36

D= -34

here it has no real root

But it has imagnary root

So, √D=√17i

x= (-b±√D)/2a

x=(√2+√17i)/2√3  and (√2-√17i)/2√3

Answer 2

Answer:

Your answer

I hope it will you