Question

Solve the equation:3k^2-4k+9=0

Answer 1

Answer:

Step-by-step explanation:

Discriminant=b^2-4ac

D=(-4) ^2-4×3×9

D=16-108

D=-92<0

Discriminant is smaller than 0 so this equation has no roots.

Answer 2

Answer:

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Step-by-step explanation:

3k^2-4k+9 = 0

k = -4+√16-108 / 6 ; -4-√16-108 / 6

k = (-4+√92 i)/6 ; (-4-√92 i)/6

so both roots are imaginary roots.

because D = b^2-4ac < 0