solve the equation
3x^{2} =2(x - 1)+7
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Answered by
1
Answer:
3x²=2(x-1)+7
3x²=2x-2+7
3x²=2x+5
3x²-2x-5=0
3x²-5x+3x-5=0
x(3x-5)+1(3x-5) =0
(x+1)(3x-5) =0
x= - 1 or x= 5/3
Hope it helps you :)
Answered by
28
3x²=2(x-1)+7
3x²=2x-2+7
3x²=2x+5
3x²-2x-5=0
3x²-5x+3x-5=0
x(3x-5)+1(3x-5) =0
(x+1)(3x-5) =0
x= - 1 or x= 5/3
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