Question

solve the equation
3x^{2} =2(x - 1)+7

Answer 1

Answer:

3x²=2(x-1)+7

3x²=2x-2+7

3x²=2x+5

3x²-2x-5=0

3x²-5x+3x-5=0

x(3x-5)+1(3x-5) =0

(x+1)(3x-5) =0

x= - 1 or x= 5/3

Hope it helps you :)

Answer 2

3x²=2(x-1)+7

3x²=2x-2+7

3x²=2x+5

3x²-2x-5=0

3x²-5x+3x-5=0

x(3x-5)+1(3x-5) =0

(x+1)(3x-5) =0

x= - 1 or x= 5/3