solve the equation 3x^2-4x+20/3=0
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Answer:
Answer
The given quadratic equation is 3x
2
−4x+
3
20
=0
This equation can also be written as 9x
2
−12x+20=0
On comparing this equation with ax +bx+c=0, we obtain a=9,b=−12 and c=20
Therefore teh discriminant of the given equation is
D=b
2
−4ac=(−12)
2
−4×9×20=144−720=−576
Therefore, the required solutions are
=
2a
−b±
D
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