Solve the equation.
3x
2 + 5x + 7
------------------
10x + 14
= 3x
2 + 4x + 3
-------------------
8x + 6
Answers
Given, 3x^2 + 5x + 7 = 0
Put x = 0 in above equation :
0 + 0 + 7 = 0 (which is not possible)
Put x = 1 in above equation :
3 + 5 + 7 = 0 (which is not possible)
Put x = 2 in above equation :
12 + 10 + 7 = 0 (which is not possible)
From above equations we can conclude that for any value for x > 2, 3x^2 will always be positive and will be greater than 5x.
So it's not possible for any positive value of x.
As (positive) +(positive) +(positive) cannot be zero.
Now, check for negative values.
As we know 3x^2 will always be positive and (3x^2 + 7) will always be greatest than 5x for any value of x. So,
{(3x^2 + 2) - 5x } > 0
So no such real values of x exists which can satisfy the given equation.
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Factor
2
out of
8
x
.
2
(
4
x
)
−
6
Factor
2
out of
−
6
.
2
(
4
x
)
+
2
(
−
3
)
Factor
2
out of
2
(
4
x
)
+
2
(
−
3
)
.
2
(
4
x
−
3
)
