Solve the equation....
3x-4(2x-5) =2(x-1) +5/2
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Step-by-step explanation:
taking LHS
3x-4(2x-5)
3x(2x-5)-4(2x-5)
6x^2-15x-8x+20
6×^2-23x+20......EQ1
Now taking RHS
2(x-1)+5÷2
multipling eq by 2
4(x-1)+5
4x+1......EQ2
NOW compating eq 1 and 2 we get
6x^2-23x+20=4x+1
6x^2-23x+20=4x+1
6x^2-23x+20-4x-1=0
6x^2-27x-19 =0
is the quadratic equation
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