solve the equation 3x+4y=11 find the value of y when x=1
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Answered by
1
3x+4y=11
when x=1
then, 3*1+4y=11
=3+4y=11
4y=11-3
4y=8
y=8/4
y=2
when x=1
then, 3*1+4y=11
=3+4y=11
4y=11-3
4y=8
y=8/4
y=2
Answered by
0
3x+4y=11
3(1)+4y=11
3+4y=11
4y=11-3
4y=8
y=8-4
y=4
3(1)+4y=11
3+4y=11
4y=11-3
4y=8
y=8-4
y=4
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