solve the equation 3x+4y=18,2x-5y=-11 by substitution method
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Given Equation
➝3x + 4y = 18 (i)
➝2x - 5y = -11 (ii)
To find
➝Value of x and y by using Substitution Method
Now Take (i)eq
➝3x + 4y = 18 (i)
➝3x = 18 - 4y
➝x = (18 - 4y)/3 (iii)
Now put the value of x on (ii)eq
➝2x - 5y = -11 (ii)
➝2(18 - 4y)/3 -5y = -11
By taking LCM we get
➝2(18 - 4y ) - 15y = - 11×3
➝36 - 8y - 15y = -33
➝-23y = -33-36
➝-23y = -69
➝23y = 69
➝y = 69/23
➝y = 3
Now Put the value of y on (iii) eq
➝x = (18 - 4y)/3 (iii)
➝x = ( 18 - 4×3)/3
➝x = (18 - 12)/3
➝x = 6/3
➝x = 2
Answer
➝x = 2 and y = 3
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