Solve the equation
3x+4y=7
2xy+3=0
Answers
Answer:
There are several ways to solve this style of problem. We'll try the two methods I use most frequently and the writer can choose which approach they prefer.
SUBSTITUTION
Provided that the equations are linearly independent, I usually use substitution.
3x + 4y - 7 = 0 Equation (1)
2x + y + 2 = 0 Equation (2)
From Equation (2), y = - 2x - 2 or - 2(x + 1 )
y = [ - 2( x + 1 ) ] Equation (3)
Substitute “ y “ from Equation (3) into Equation (1).
Therefore:
3x + 4y - 7 = 0 so
3x + ( 4 )*[ -2( x + 1 ) ] - 7 = 0 so
3x - 8x -8 -7 = 0 so
( - 5x ) - (15 ) = 0 or
( 5x ) = (- 15 ) or
x =( - 3 )
Substitute the value of “ x “ into Equation (2).
2x + y + 2 = 0 Equation (2)
( 2 ) * (- 3 ) + ( y ) + ( 2 ) = ( 0 ) so
(- 6 ) + ( y ) + ( 2 ) = ( 0 ) so
( y ) = ( + 4 )
Check values
x = ( - 3 ) and ( y ) = ( + 4 ).
Equation (1) is 3x + 4y - 7 = 0
3( - 3 ) + 4( 4 ) - ( 7 ) = ( 0 ) Confirmed
Equation (2) is 2x + y + 2 = 0
2( - 3 ) + ( 4 ) + ( 2 ) = ( 0 )
( - 6 ) + ( 4 ) + ( 2 ) = ( 0 ) Confirmed
GAUSS METHOD
3x + 4y - 7 = 0 Equation (1)
2x + y + 2 = 0 Equation (2)
I'm assuming (rightly or wrongly) that the question writer is not well versed in the GAUSS methodology, so I've provided more detail than is strictly necessary.
Step-by-step explanation:
mark as brainliest