Question

solve the equation: [(3x-8)(3)(3)][(3)(3x-8)(3)][(3)(3)(3x-8)]=0​

Answer 1

Expanding the determinant along C1, we have Δ = (3x – 2)(1)[(3x – 11)(3x – 11) – (0)(0)] ⇒ Δ = (3x – 2)(3x – 11)(3x – 11) ∴ Δ = (3x – 2)(3x – 11)2 The given equation is Δ = 0. ⇒ (3x – 2)(3x – 11)2 = 0 Case – I : 3x – 2 = 0 ⇒ 3x = 2 ∴ x = 2323 Case – II : (3x – 11)2 = 0 ⇒ 3x – 11 = 0 ⇒ 3x = 11 ∴ x = 113113 Thus, 2323 and 113113 are the roots of the given determinant equation

Answer 2

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