Question

Solve the equation 3x-y=40, 2x-y=25

Answer 1

Answer:

$value \: of \: x = 15 \\ \\ value \: of \: y = 5$

Step-by-step explanation:

$3x - y = 40 .........(1) \\ 2x - y = 25........(2) \\ from \: equation \: (1) \: and \: (2) \\ you \: get \: subtract \: both \: the \: equation \: and \: eleminate \:( y) \\ x = 15 \\ put \: x = 15 \: in \: equation \: (1) \\ 3(15) - y = 40 \\ 45 - y = 40 \\ - y = - 5 \\ y = 5$

Answer 2

QUESTION:

Solve the equation 3x-y=40, 2x-y=25

ANSWER:

Let,

$3x - y = 40.....(eq.1)$

$2x - y = 25....(eq.2)$

☆ We use the elimination method to solve the equation.

Now,

Adding equation 1 and equation 2;

$\blue {(3x - y) + (2x - y) = 40 + 25}$

$3x - y + 2x - y = 65$

$5x = 65$

$\huge\purple {x = 15}$

☆putting the value of x in equation 1;

$3(15) - y = 40 \\ 45 - y = 40 \\ -y = 40 - 45 \\ - y = - 5$

$\huge\green {y = 5}$