Solve the equation 3x-y=5 and 3x+3y=21 by elimination by substitution method
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Answer:
x = 3 , y = 4
Step-by-step explanation:
Elimination Method :
3x - y = 5 .......(1)
3x + 3y = 21 .......(2)
Now we'll subtract (2) from (1),
(1) - (2) =
-4y = -16
∴ y = 4
Now Substituting the value of y in (1) ;
∴ x = 3
Substitution Method :
3x - y = 5 .......(1)
3x + 3y = 21 .......(2)
Now, Taking (1),
y = 3x - 5 .......(3)
Now Substitute the Value of y from (3) in (2) ;
3x + 3 [ 3x - 5 ] = 21
3x + 9x - 15 = 21
12x - 15 = 21
12x = 36
∴ x = 3
Now Substituting the value of x in (1) ;
∴ y = 4
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