solve the equation 3x+y-z=2 2x-y+2z=6 2x+y-2z=-2
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3x+y-z =2----->[1]
2x-y+2z =6----->[2]
2x+y-2z = -2--->[3]
[1]+[2]=>5x+z=9--->[4]
[2]+[3]=>4x=4
=> x=1
From [4],
z=9-5x
=9-5(1)
=9-5
=4
From[1]
y=2+z-3x
=2+4-3
=2+1
=3
Therefore x=1,y=3,z=4
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