Math, asked by pari1165, 9 months ago

Solve the equation 3x² + x -14 = 0 in the set of integers.​

Answers

Answered by hasnainrabby
5

Answer:

x = 2 or -7/3

Step-by-step explanation:

3x^2 + x -14 =0

3x^2 -6x +7x -14 = 0 [ Middle term applied ]

3x( x -2) + 7(x-2)=0

(x-2)(3x+7)=0

So. Or,

(x-2)=0. (3x+7)=0

x=2. x= -7/3

Hope it helps you.

Answered by imamuddini681
1

Step-by-step explanation:

3x^2+x-14 =0

3x^2-6x+7x-14

3x(x-2)+7(x-2)

(3x+7)(x-2)

x=-7/3 &x=2

x=2

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