Question

Solve the equation 3xsquare+x-14=0 in the set of integers result

Answer 1

Answer :

= ${3x}^{2}$ + x - 14 = 0

= ${3x}^{2}$ + 7x - 6x - 14 = 0

= x (3x + 7) - 2 ( 3x + 7) = 0

= (3x + 7) (x - 2) = 0

• Separate into possible cases.

= (3x + 7) = 0

= (x - 2) = 0

• Solve the equations.

= x = $\dfrac{-7}{3}$

= x = 2

So, these two are solutions of this equation.

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