Solve the equation -4+(-1) +2+-------+x=437
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Answer:
Step-by-step explanation:
Given the series [−4+(−1)+2+⋅⋅⋅⋅x=437] in A.P.
Then,
a=−4
d=−1−(−4)=3
Sn =437
Then, using sum formula A.P.
Sn = n/2[2a+(n−1)d]
⇒437= n/2 [2(−4)+(n−1)3]
⇒874=n[−8+3n−3]
⇒874=3n^2−11n
⇒3n^2 −11n=874
⇒3n^2 −11n−874=0
⇒3n^2−(57−46)n−874=0
⇒3n^2 −57n−46n−874=0
⇒3n(n−19)−46(n−19)=0
⇒(n−19)(3n−19)=0
⇒n−19=0,3n−19=0
⇒n=19. ,n=19/3
Hence, n=19
So,
x=a+(n−1)d
x=−4+(19−1)3
x=−4+54
x=50
Hence, this is the answer.
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