Question

solve the equation
-4+(-1)+2.....y=437
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Answer 1

Solution:

It seems to like an A.P.

with its first term a = -4

common difference d = -1-(-4)=3

to find the value of y,we had to find its last term and total terms,

As sum is given = 437

Apply formula of Sum

$sn = \frac{n}{2} \bigg(2a + (n - 1)d\bigg) \\ \\ 437 = \frac{n}{2} \bigg(2( - 4) + (n - 1)3\bigg) \\ \\ 437 = \frac{n}{2} ( - 8 + 3n - 3) \\ \\ 874 = n(3n - 11) \\ \\ 3 {n}^{2} - 11n - 874 = 0 \\ \\ 3 {n}^{2} - 57n + 46n - 874 = 0 \\ \\ 3n(n - 19) + 46(n - 19) = 0 \\ \\ (n - 19)(3n + 46) = 0 \\ \\ n = 19 \\ \\ and \: n = \frac{ - 46}{3}$
Discard -ve and fractional value of n.

Thus n = 19

So, $y = T_{19}= a+18d$

y = -4+18(3)

y = -4+54

y = 50

Hope it helps you

Answer 2

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This is the best possible answer

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