Solve the equation 4(2y+1)=7+3(y-1)
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0
Answer:
4
(
2
+
1
)
=
7
+
3
(
−
1
)
{\color{#c92786}{4(2y+1)}}=7+3(y-1)
4(2y+1)=7+3(y−1)
8
+
4
=
7
+
3
(
−
1
please give this answer brainest
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