Math, asked by guptachhavi298, 4 months ago

Solve the equation 4 sin²co-3 =0

Answers

Answered by devip649

1

Step-by-step explanation:

Explanation:

Let

z

=

sin

(

x

)

Then:

4

z

2

−

3

=

0

z

2

=

3

4

⇒

z

=

√

3

2

⇒

sin

(

x

)

=

√

3

2

sin

−

1

sin

(

x

)

=

sin

−

1

(

√

3

2

)

⇒

x

=

π

3

π

−

π

3

=

2

π

3

2

π

−

2

π

3

=

4

π

3

2

π

−

π

3

=

5

π

3

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