solve the equation 4a^3_6a^2+1=0
Answers
Answer:
Hello mate..
Step-by-step explanation:
Answer:
a = 1 and b = 4
Step-by-step explanation:
Given expression is 2x^3 - ax^2 - 8x + b. If ( 2x - 1 ) and ( x + 2 ) are its factors, its value must be 0 for x = 1/2 and for x = -2.
For x = 1 / 2
⇒ 2(1/2)³ - a(1/2)² - 8(1/2) + b = 0
⇒ 2(1/8) - a(1/4) - 8(1/2) + b = 0
⇒ (1/4) - (a/4) - 4 + b = 0
⇒ ( 1 - a - 16 + 4b ) / 4 = 0
⇒ 4b - a - 15 = 0
⇒ 4b - a = 15
For x = - 2
⇒ 2(-2)³ - a(-2)² - 8(-2) + b = 0
⇒ 2(-8) - a(4) - 8(-2) + b = 0
⇒ - 16 - 4a + 16 + b = 0
⇒ b - 4a = 0
⇒ 4a = b
Hence,
4b - a = 15
4( 4a ) - a = 15
16a - a = 15
15a = 15
a = 1
Hence, b = 4a = 4(1) = 4
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Step-by-step explanation:
a(4a²+6a+1)=0
a=0
4a²+6a+1=0
solve by formula method u get urs answer