solve the equation 4x +1 = x - 2 and represent the solution on the number line
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Answered by
6
Hi there !!
Here's your answer
Given,
to find the value of x in
4x + 1 = x - 2
Transposing x to LHS and 1 to RHS,
we have,
4x - x = -2 - 1
3x = -3
x = -3/3
x = -1
[ Number line in the attachment ]
Here's your answer
Given,
to find the value of x in
4x + 1 = x - 2
Transposing x to LHS and 1 to RHS,
we have,
4x - x = -2 - 1
3x = -3
x = -3/3
x = -1
[ Number line in the attachment ]
Attachments:
arjun661:
thanks
Answered by
8
Hey there !
Solving a linear equation :
4x + 1 = x -2
Transposing x terms to LHS and constants to RHS.,
4x - x = -2 -1
3x = -3
x = -3/3
x = -1 .
Solving a linear equation :
4x + 1 = x -2
Transposing x terms to LHS and constants to RHS.,
4x - x = -2 -1
3x = -3
x = -3/3
x = -1 .
Attachments:
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