Question

solve the equation 4x-5y+16=0,2x+y-6=0
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Answer 1

Answer:

We have system of equation:

A:4x−5y+16=0−−−(1)

B:2x+y−6=0−−−−(2)

For A

x0−41

y16/504

For B

x031

y604

From solving equation (1) & (2), we get only one point (1,4) as

−7y+28=0⇒y=4

4x−5y+16=04x+2y−12=0−−+

,x=

2

6−y

=

2

2−4

=1

So, the vertices are (−4,0),(1,4) & (3,0)

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Answer 2

Explanation:

4x-5y+16=2x+y-6

4x-2x+16+6=y+5y

2x+22=6y

2{x+11}=6y

x+11=6y/2

x+11=3y

x=3y-11

2x+y-6=0

2{3y-11}+y-6=0

6y-22+y-6=0

7y-28=0

7y=28

y=28/7

y=4

x+11=3y

x=3[4]-11

x=12-11

x=1