Question

solve the equation 4y=2/3(3y-1)​

Answer 1

Answer:How to solve your question

Your question is

4

=

2

3

(

3

−

1

)

4y=\frac{2}{3}(3y-1)

4y=32​(3y−1)

Solve

1

Combine multiplied terms into a single fraction

4

=

2

3

(

3

−

1

)

4y=\frac{2}{3}(3y-1)

4y=32​(3y−1)

4

=

2

(

3

−

1

)

3

4y=\frac{2(3y-1)}{3}

4y=32(3y−1)​

2

Distribute

3

Multiply all terms by the same value to eliminate fraction denominators

4

Simplify

5

Subtract  

6

6y

6y

from both sides of the equation

3 more steps

Solution

=

−

1

3

Step-by-step explanation:

Answer 2

4y = 6y - 2/3

2/3 = 6y - 4y

2/3 = 2y

2y = 2/3

y = 2/3/2

y = 2/3×1/2

y = 1/3 answer