solve the equation 5-3(5t+2) = 4(7-3t)+1
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Given, 5t−3=3t−5
⇒5t−3t=−5+3
⇒2t=−2
⇒t=−1
Check-
Substituting t=−1
LHS =5t−3=5×(−1)−3=−8
RHS =3t−5=3×(−1)−5=−8
∴ LHS = RHS
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Answer:
t=-10. Hope this will help you
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