Solve the equation
5(y-3)=3(4y+1)+8
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The given equation,
5 (y-3) = 3 (4y+1) +8
5y-15 = 12y +3 +8
12y - 5y + 11+15 = 0
7y + 26 = 0
y = -26/7
Hope it will help you
5 (y-3) = 3 (4y+1) +8
5y-15 = 12y +3 +8
12y - 5y + 11+15 = 0
7y + 26 = 0
y = -26/7
Hope it will help you
Ritikbhat628:
How do u know that u have to keep 12y at left of 5y
12y is greater than 5y
Then 5y come on the side of 12y
Thnx
Ur welcome
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