Math, asked by nikitha9930, 11 hours ago

solve the equation 5(z+3)=4(2z+1) ​

Answers

Answered by ManiDareddy
1

5(z + 3) = 4(2z + 1)

5z + 15 = 8z + 4

15 - 4 = 8z - 4z

11 = 4z

z =  \frac{11}{4}

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Answered by nihasrajgone2005
14

Answer:

5(z+3)=4(2z+1)

5z + 15 = 8z + 45z+15=8z+4

15 - 4 = 8z - 4z15−4=8z−4z

11 = 4z11=4z

11 = 4z

z = 11/4

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