solve the equation 5(z+3)=4(2z+1)
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Answer:
5(z+3)=4(2z+1)
5z + 15 = 8z + 45z+15=8z+4
15 - 4 = 8z - 4z15−4=8z−4z
11 = 4z11=4z
11 = 4z
z = 11/4
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