solve the equation 500x+100(200-x)= 800
Answers
Answered by
1
500x + 100(200-x) = 800
500x + (100×200)-(100×x) = 800
500x + 20000 - 100x = 800
500x - 100x = 800-20000
400x = -19200
x = -19200/400
x = -48
500x + (100×200)-(100×x) = 800
500x + 20000 - 100x = 800
500x - 100x = 800-20000
400x = -19200
x = -19200/400
x = -48
Answered by
2
500x + 100 (200 - x) = 800
500x + 20000 - 100x = 800
500x - 100x = 800 - 20000
400x = -19200
x = -19200/400
x = -48
500x + 20000 - 100x = 800
500x - 100x = 800 - 20000
400x = -19200
x = -19200/400
x = -48
Ankit1234:
mark my answer as brainliest
Similar questions