Math, asked by ahadia13, 2 months ago

solve the equation (5p+1)(p+4) =2(7p+5)​

Answers

Answered by siddhantjani25
0

Answer:

Step-by-step explanation: (5p + 1)(p + 4) = 2(7p + 5)

= 5p(p+4)+1(p+4) = 2(7p + 5)

=5p²+ 20p + p + 4 = 14p + 10

=5p² + 21p + 4 = 14p + 10

= 5p² + 21p -14p + 4 = 10

=5p² + 7p +4 = 10

= 5p² + 7p = 10 -4

=5p² + 7p = 6

Answered by dassrijani1610
1

Answer:

3/5 and -2

Step-by-step explanation:

equating left hand side equation we get

(5p + 1)(p + 4)

5 {p}^{2}  + 20p + 1p + 4

5 {p}^{2}  + 21p + 4

equating right hand side equation we get

2(7p + 5) = 14p + 10

NOW EQUATING BOTH

5 {p}^{2}  + 21p + 4 = 14p + 10 \\

5 {p}^{2}  + 7p - 6 = 0 \\

5 {p}^{2}  + 10p - 3p - 6 = 0

 (5p - 3)(p + 2) = 0

value of p = 3/5 and -2

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