Math, asked by rahulkumar8985, 1 year ago

Solve the equation 7+4√3= a+b√3the whole sqare

Answers

Answered by desi42
0

 {(7 + 4 \sqrt{3} )}^{2}

=

 {7}^{2}  +  {48}^{2}  + 56 \sqrt{3}


master55538: see once
desi42: bro it is the identity of (a+b) whole square
desi42: if you don't know this identity then i will tell you
master55538: yes I know but when we square the answer will be 7*7+48+56root3
desi42: (a+b) whole square =a square+b square +2ab
master55538: OK substitute and see
desi42: sorry i do a mistake in the product
master55538: no problem
desi42: Ok meet you later
desi42: please brainliest my answer
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