Math, asked by rahulkumar8985, 10 months ago

Solve the equation 7+4√3= a+b√3the whole sqare

Answers

Answered by desi42

${(7 + 4 \sqrt{3} )}^{2}$

${7}^{2} + {48}^{2} + 56 \sqrt{3}$

master55538: see once

desi42: bro it is the identity of (a+b) whole square

desi42: if you don't know this identity then i will tell you

master55538: yes I know but when we square the answer will be 7*7+48+56root3

desi42: (a+b) whole square =a square+b square +2ab

master55538: OK substitute and see

desi42: sorry i do a mistake in the product

master55538: no problem

desi42: Ok meet you later

desi42: please brainliest my answer

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