Question

Solve the equation 77(m+5)m+5 = 33(2m−7)2⁢m-7​

Answer 1

Answer:

Answer:

(i) x + 3 = 0

LHS = x + 3

Put x = 3, we get

LHS = 3 + 3 = 6 ≠ RHS

So, the equation is not satisfied.

(ii) x + 3 = 0

LHS = x + 3

Put x = 0, we get

LHS = 0 + 3 = 3 ≠ RHS

So, the equation is not satisfied.

(iii) x + 3 = 0

LHS = x + 3

Put x = -3, we get

LHS = -3 + 3 = 0 = RHS

So, the equation is satisfied.

(iv) x - 7 = 1

LHS = x - 7

Put x = 7, we get

LHS = 7 - 7 = 0 ≠ RHS

So, the equation is not satisfied.

(v) x - 7 = 1

LHS = x - 7

Put x = 8, we get

LHS = 8 - 7 = 1 = RHS

So, the equation is satisfied.

(vi) 5x = 25

LHS = 5x

Put x = 0, we get

LHS = 5 * 0 = 0 ≠ RHS

So, the equation is not satisfied.

(vii) 5x = 25

LHS = 5x

Put x = 5, we get

LHS = 5 * 5 = 25 = RHS

So, the equation is satisfied.

 (viii) 5x = 25

LHS = 5x

Put x = -5, we get

LHS = 5 * (-5) = -25 ≠ RHS

So, the equation is not satisfied.

 (ix) m/3 = 2

LHS = m/3

Put m = -6, we get

LHS = -6/3 = -2 ≠ RHS

So, the equation is not satisfied.

(x) m/3 = 2

LHS = m/3

Put m = 0, we get

LHS = 0/3 = 0 ≠ RHS

So, the equation is not satisfied.

(xi) m/3 = 2

LHS = m/3

Put m = 6, we get

LHS = 6/3 = 2 = RHS

So, the equation is satisfied